by johnnic » Wed Jul 14, 2010 5:37 am
In an event in which there can only be one of two outcomes (eg a tennis match) it is a simple process to establish the 'green up' bet without any reference to previous bets one has taken.
=(MAX(outcome 1, outcome 2) - MIN(outcome1, outcome2))/the current back/lay odds (dependant on which provides the better return).
I would like to be able to extend this approach to instances when there are three (but not more) possible outcomes.
Can anyone throw any (useful) advice my way?
John