A silly question that i just cannot find the answer to.

[adsy22]

If i place a bet in the back column for $100 at $3.00 and am looking to lay and green up. If the market moves 5 ticks away and my stop loss kicks in and lay's the selection, what is my loss on that selection before greening up

I know it is a simple question but one that is driving me nuts and am finding hard to answer.
Any insight guy's....please!

[greenfingers]

The increment between odds varies depending on what the odds are. Below 3, odds decrease 0.02 at a time - i.e. 2.98, 2.96 etc. Above 3 they increase 0.05 at a time - i.e. 3.05, 3.1 etc

So, if you back @ 3 and the market drifts 5 ticks, the market will be at 3.25.

Your loss before redding-up is: $100*0.25=$25. (0.25 is 3.25-3). Redded-up the loss is therefore 25/3.25=$7.69

BTW, backing at the point where odds-increments change (e.g. at 2,3,4,6 etc) is a very poor move - in this example, you are risking 0.05 if the market drifts 1 tick and you only stand to make 0.02 if the market does indeed shorten 1 tick. I don't like those odds!

[GaryRussell]

The stop loss will kick in when the best back odds reach 3.25 and it will request best back odds plus 1 tick, therefore a $100 lay bet will be placed at 3.30.

Your potential loss if the selection wins will be $30.00

[adsy22]

thanks guys really appreciated just confirmed my first thought and wow what a quick reply